std::bit_xor
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< cpp | utility | functional
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| Defined in header <functional>
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| template< class T > struct bit_xor; |
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Función objeto de realizar bit a bit XOR. Efectivamente llama operator^ en
T tipo .Original:
Function object for performing bitwise XOR. Effectively calls operator^ on type
T.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Contenido |
[editar] Tipos de miembros
| Tipo
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
result_type
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T
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first_argument_type
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T
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second_argument_type
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T
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[editar] Las funciones miembro
| operator() |
devuelve el resultado de XOR bit a bit de dos argumentos Original: returns the result of bitwise XOR of two arguments The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (miembro público función) |
std :: bit_xor ::Original:std::bit_xor::The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.operator()
Original:
std::bit_xor::
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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| T operator()( const T& lhs, const T& rhs ) const; |
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Returns the result of bitwise XOR of lhs and rhs.
Parameters
| lhs, rhs | - | valores para calcular XOR bit a bit de
Original: values to compute bitwise XOR of The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Return value
The result of lhs ^ rhs.
Exceptions
(none)
Possible implementation
T operator()(const T &lhs, const T &rhs) const { return lhs ^ rhs; } |