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std::numeric_limits::lowest

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std::numeric_limits
 
static constexpr T lowest()
(desde C++11)
Devuelve el menor valor finito representable por la T tipo numérico, es decir, un valor finito x de tal manera que no hay ningún otro valor finito y donde y < x. Esto es diferente de std::numeric_limits<T>::min() para tipos de punto flotante. Sólo tiene sentido para los tipos acotados .
Original:
Returns the lowest finite value representable by the numeric type T, that is, a finite value x such that there is no other finite value y where y < x. This is different from std::numeric_limits<T>::min() for floating-point types. Only meaningful for bounded types.
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Contenido

[editar] Valor de retorno

T std::numeric_limits<T>::lowest()
/* non-specialized */ T();
bool false
char CHAR_MIN
signed char SCHAR_MIN
unsigned char 0
wchar_t WCHAR_MIN
char16_t 0
char32_t 0
short SHRT_MIN
unsigned short 0
int INT_MIN
unsigned int 0
long LONG_MIN
unsigned long 0
long long LLONG_MIN
unsigned long long 0
float -FLT_MAX
double -DBL_MAX
long double -LDBL_MAX

[editar] Notas

Si bien no es cierto para C + + fundamental flotante Poing tipos, un tercero tipo de punto flotante T puede existir tal que std::numeric_limits<T>::lowest() != -std::numeric_limits<T>::max() .
Original:
While it's not true for fundamental C++ floating-poing types, a third-party floating-point type T may exist such that std::numeric_limits<T>::lowest() != -std::numeric_limits<T>::max().
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[editar] Excepciones

noexcept specification:  
noexcept
  (desde C++11)

[editar] Ejemplo

Demuestra mínimo, máximo, mínimo y para tipos de punto flotante
Original:
Demonstrates min, max, and lowest for floating-point types
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#include <limits>
#include <iostream>
int main()
{
 
    std::cout << "std::numeric_limits<T>::min():\n"
              << "\tfloat: " << std::numeric_limits<float>::min()
              << " or " << std::hexfloat << std::numeric_limits<float>::min() << '\n'
              << "\tdouble: " << std::defaultfloat << std::numeric_limits<double>::min()
              << " or " << std::hexfloat << std::numeric_limits<double>::min() << '\n';
    std::cout << "std::numeric_limits<T>::lowest():\n"
              << "\tfloat: " << std::defaultfloat << std::numeric_limits<float>::lowest()
              << " or " << std::hexfloat << std::numeric_limits<float>::lowest() << '\n'
              << "\tdouble: " << std::defaultfloat << std::numeric_limits<double>::lowest()
              << " or " << std::hexfloat << std::numeric_limits<double>::lowest() << '\n';
    std::cout << "std::numeric_limits<T>::max():\n"
              << "\tfloat: " << std::defaultfloat << std::numeric_limits<float>::max()
              << " or " << std::hexfloat << std::numeric_limits<float>::max() << '\n'
              << "\tdouble: " << std::defaultfloat << std::numeric_limits<double>::max()
              << " or " << std::hexfloat << std::numeric_limits<double>::max() << '\n';
}

Output:

std::numeric_limits<T>::min():
        float: 1.17549e-38 or 0x1p-126
        double: 2.22507e-308 or 0x1p-1022
std::numeric_limits<T>::lowest():
        float: -3.40282e+38 or -0x1.fffffep+127
        double: -1.79769e+308 or -0x1.fffffffffffffp+1023
std::numeric_limits<T>::max():
        float: 3.40282e+38 or 0x1.fffffep+127
        double: 1.79769e+308 or 0x1.fffffffffffffp+1023

[editar] Ver también

[estático]
devuelve el menor valor finito del tipo dado
Original:
returns the smallest finite value of the given type
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(miembro estático público función) [edit]
[estático]
devuelve el menor valor positivo subnormal de lo dado tipo de punto flotante
Original:
returns the smallest positive subnormal value of the given floating-point type
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(miembro estático público función) [edit]
[estático]
devuelve el mayor valor finito del tipo dado
Original:
returns the largest finite value of the given type
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(miembro estático público función) [edit]