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std::set_intersection

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< cpp‎ | algorithm

 
 
Algoritmo biblioteca
Funciones
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Functions
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Para no modificar la secuencia de las operaciones
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Non-modifying sequence operations
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Modificación de la secuencia de operaciones
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Modifying sequence operations
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Particionamiento operaciones
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Partitioning operations
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Clasificación de las operaciones (en rangos ordenados)
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Sorting operations (on sorted ranges)
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Las operaciones binarias de búsqueda (en rangos ordenados)
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Binary search operations (on sorted ranges)
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Conjunto de operaciones (en rangos ordenados)
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Set operations (on sorted ranges)
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Operaciones del montón
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Heap operations
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Mínimo / máximo de operaciones
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Minimum/maximum operations
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Operaciones numéricas
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Numeric operations
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C biblioteca
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C library
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Defined in header <algorithm>
template< class InputIt1, class InputIt2, class OutputIt >

OutputIt set_intersection( InputIt1 first1, InputIt1 last1,
                           InputIt2 first2, InputIt2 last2,

                           OutputIt d_first );
(1)
template< class InputIt1, class InputIt2,

          class OutputIt, class Compare >
OutputIt set_intersection( InputIt1 first1, InputIt1 last1,
                           InputIt2 first2, InputIt2 last2,

                           OutputIt d_first, Compare comp );
(2)
Construye un comienzo rango ordenados en d_first compuesto de elementos que se encuentran en ambos rangos ordenados [first1, last1) y [first2, last2). La primera versión espera tanto de entrada va a ser resuelto con operator<, la segunda versión espera que se solucionó con la comparación comp función dada. Si algún elemento se encuentra m veces en [first1, last1) y n veces en [first2, last2), los elementos std::min(m, n) primero se copiarán desde el primer rango al rango de destino. El orden de los elementos equivalentes se conserva. El rango resultante no se puede solapar con cualquiera de los rangos de entrada .
Original:
Constructs a sorted range beginning at d_first consisting of elements that are found in both sorted ranges [first1, last1) and [first2, last2). The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp. If some element is found m times in [first1, last1) and n times in [first2, last2), the first std::min(m, n) elements will be copied from the first range to the destination range. The order of equivalent elements is preserved. The resulting range cannot overlap with either of the input ranges.
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Contenido

[editar] Parámetros

first1, last1 -
la primera gama de elementos a examinar
Original:
the first range of elements to examine
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first2, last2 -
la segunda gama de elementos a examinar
Original:
the second range of elements to examine
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comp - comparison function which returns ​true if the first argument is less than the second.

The signature of the comparison function should be equivalent to the following:

 bool cmp(const Type1 &a, const Type2 &b);

The signature does not need to have const &, but the function must not modify the objects passed to it.
The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively. ​

Type requirements
-
InputIt1 must meet the requirements of InputIterator.
-
InputIt2 must meet the requirements of InputIterator.
-
OutputIt must meet the requirements of OutputIterator.

[editar] Valor de retorno

Iterator allá del final de la rango construido .
Original:
Iterator past the end of the constructed range.
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[editar] Complejidad

En la mayoría de las comparaciones 2·(N1+N2-1), donde N1 = std::distance(first1, last1) y N2 = std::distance(first2, last2) .
Original:
At most 2·(N1+N2-1) comparisons, where N1 = std::distance(first1, last1) and N2 = std::distance(first2, last2).
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[editar] Posible implementación

First version
template<class InputIt1, class InputIt2, class OutputIt>
OutputIt set_intersection(InputIt1 first1, InputIt1 last1,
                          InputIt2 first2, InputIt2 last2,
                          OutputIt d_first)
{
    while (first1 != last1 && first2 != last2) {
        if (*first1 < *first2) {
            ++first1;
        } else  {
            if (!(*first2 < *first1)) {
                *d_first++ = *first1++;
            }
            ++first2;
        }
    }
    return d_first;
}
Second version
template<class InputIt1, class InputIt2,
         class OutputIt, class Compare>
OutputIt set_intersection(InputIt1 first1, InputIt1 last1,
                          InputIt2 first2, InputIt2 last2,
                          OutputIt d_first, Compare comp)
{
    while (first1 != last1 && first2 != last2) {
        if (comp(*first1, *first2)) {
            ++first1;
        } else {
            if (!comp(*first2, *first1)) {
                *d_first++ = *first1++;
            }
            ++first2;
        }
    }
    return d_first;
}


[editar] Ejemplo

#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
int main()
{
    std::vector<int> v1{1,2,3,4,5,6,7,8};
    std::vector<int> v2{        5,  7,  9,10};
    std::sort(v1.begin(), v1.end());
    std::sort(v2.begin(), v2.end());
 
    std::vector<int> v_intersection;
 
    std::set_intersection(v1.begin(), v1.end(),
                          v2.begin(), v2.end(),
                          std::back_inserter(v_intersection));
    for(int n : v_intersection)
        std::cout << n << ' ';
}

Output:

5 7

[editar] Ver también

computes the union of two sets
(función de plantilla) [edit]