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std::search

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< cpp‎ | algorithm

 
 
Biblioteca de algoritmos
Políticas de ejecución (C++17)
Operaciones no modificadoras de secuencia
(C++11)(C++11)(C++11)
(C++17)
Operaciones modificadoras de secuencia
Operaciones en almacenamiento no inicializado
Operaciones de partición
Operaciones de ordenación
(C++11)
Operaciones de búsqueda binaria
Operaciones de set (en rangos ordenados)
Operaciones de pila
(C++11)
Operaciones minimo/maximo
(C++11)
(C++17)
Permutaciones
Operaciones numéricas
Bibliotecas C
 
Definido en la cabecera <algorithm>
template< class ForwardIt1, class ForwardIt2 >

ForwardIt1 search( ForwardIt1 first, ForwardIt1 last,

                   ForwardIt2 s_first, ForwardIt2 s_last );
(1)
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate >

ForwardIt1 search( ForwardIt1 first, ForwardIt1 last,

                   ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p );
(2)
Busca la primera subsecuencia de [s_first, s_last) elementos en la [first, last - (s_last - s_first)) rango. La primera versión utiliza operator== para comparar los elementos, la segunda versión utiliza el predicado binario dado p .
Original:
Searches for the first subsequence of elements [s_first, s_last) in the range [first, last - (s_last - s_first)). The first version uses operator== to compare the elements, the second version uses the given binary predicate p.
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Contenido

[editar] Parámetros

first, last -
la gama de elementos a examinar
Original:
the range of elements to examine
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s_first, s_last -
la gama de elementos a buscar
Original:
the range of elements to search for
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p - binary predicate which returns ​true if the elements should be treated as equal.

The signature of the predicate function should be equivalent to the following:

 bool pred(const Type1 &a, const Type2 &b);

The signature does not need to have const &, but the function must not modify the objects passed to it.
The types Type1 and Type2 must be such that objects of types ForwardIt1 and ForwardIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively.

Requerimientos de tipo
-
ForwardIt1, ForwardIt2 debe reunir los requerimientos de ForwardIterator.

[editar] Valor de retorno

Iterator para el comienzo de [s_first, s_last) primera subsecuencia en la [first, last - (s_last - s_first)) rango. Si no se encuentra dicho subsecuencia, last es returned.
Original:
Iterator to the beginning of first subsequence [s_first, s_last) in the range [first, last - (s_last - s_first)). If no such subsequence is found, last is returned.
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Si [s_first, s_last) está vacía, se devuelve first. (desde C++11)
Original:
If [s_first, s_last) is empty, first is returned. (desde C++11)
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[editar] Complejidad

En la mayoría de las comparaciones S*N donde S = std::distance(s_first, s_last) y N = std::distance(first, last) .
Original:
At most S*N comparisons where S = std::distance(s_first, s_last) and N = std::distance(first, last).
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[editar] Posible implementación

Primera versión
template<class ForwardIt1, class ForwardIt2>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
                        ForwardIt2 s_first, ForwardIt2 s_last)
{
    for (; ; ++first) {
        ForwardIt1 it = first;
        for (ForwardIt2 s_it = s_first; ; ++it, ++s_it) {
            if (s_it == s_last) {
                return first;
            }
            if (it == last) {
                return last;
            }
            if (!(*it == *s_it)) {
                break;
            }
        }
    }
}
Segunda versión
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
                        ForwardIt2 s_first, ForwardIt2 s_last, 
                        BinaryPredicate p)
{
    for (; ; ++first) {
        ForwardIt1 it = first;
        for (ForwardIt2 s_it = s_first; ; ++it, ++s_it) {
            if (s_it == s_last) {
                return first;
            }
            if (it == last) {
                return last;
            }
            if (!p(*it, *s_it)) {
                break;
            }
        }
    }
}

[editar] Ejemplo

[editar] Ver también

encuentra la última secuencia de elementos en un cierto rango
Original:
finds the last sequence of elements in a certain range
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(plantilla de función) [editar]
determina si dos conjuntos de elementos son los mismos
Original:
determines if two sets of elements are the same
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(plantilla de función) [editar]
encuentra el primer elemento que satisfaga los criterios específicos
Original:
finds the first element satisfying specific criteria
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(plantilla de función) [editar]
devuelve true si el rango es menor que otro lexicográfico
Original:
returns true if one range is lexicographically less than another
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(plantilla de función) [editar]
encuentra la primera posición donde dos rangos difieren
(plantilla de función) [editar]
Busca un número de copias consecutivas de un elemento en un rango
Original:
searches for a number consecutive copies of an element in a range
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(plantilla de función) [editar]